Del with Superscript in Carroll's Equation

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SUMMARY

The discussion centers on Carroll's equation (1.116) from "Spacetime and Geometry," specifically addressing the term ##\partial^{\nu} p## for a perfect fluid. Participants confirm that in flat Minkowski spacetime, ##\partial^{\nu} p## is equivalent to ##\eta^{\nu \sigma} \partial_{\sigma} p##, as the metric can be used to raise indices on derivatives. They emphasize that for a more general context involving curved spacetime, the covariant derivative should be utilized instead of simple partial derivatives.

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  • Knowledge of tensor notation and index manipulation
  • Basic grasp of covariant derivatives in differential geometry
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Pencilvester
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In Carroll’s “Spacetime and Geometry” his equation (1.116) for ##\partial_{\mu} T^{\mu \nu}## for a perfect fluid ends with the term ##... + ~\partial^{\nu} p##. First of all, in order for this equation to really be general, it would need to use the covariant derivative instead of the simple partials, right? I assume he’s assuming a flat Minkowski spacetime where dels work just fine because it’s at the beginning of the book. But here’s the main question: is ##\partial^{\nu} p## just the same as ##\eta^{\nu \sigma} \partial_{\sigma} p## here? I’ve just never seen a del with a superscript before, and he offers no explanation for it.
 
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Pencilvester said:
in order for this equation to really be general, it would need to use the covariant derivative instead of the simple partials, right?

I think he's assuming flat spacetime in Cartesian coordinates at this point in the book, in which case the two are the same. For a general curved spacetime or general curvilinear coordinates, yes, you would have to use the covariant derivative.

Pencilvester said:
is ##\partial^{\nu} p## just the same as ##\eta^{\nu \sigma} \partial_{\sigma} p## here?

Yes. You can use the metric to raise an index on anything that has a lower index, including derivative operators. (The same applies to covariant derivatives when you are in a general curved spacetime or general curvilinear coordinates.)
 
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PeterDonis said:
Yes.
Thanks!
 

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