Demoivre's Theorem: Am I doing it right?

  • Thread starter pugfug90
  • Start date
  • #1
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Homework Statement


Use Demoivre's Theorem to evaluate w^2, if w=3(cos30degs+ising30degs)
PS, it's really pi/6, but I converted it to 30 degrees since I can't write on the screen..

Homework Equations


z^n=r^n(cos n*theta + i sin n*theta)

The Attempt at a Solution



w^2=3^2 (cos 2*30degs + i sin 2*30degs_
w^2=9(cos60degs+isin60degs)
w^2=9(0.5+i [square root of 3]/2)
w^2=(9/2)+9i[square root of 3]/2

===
I copied the test review answer key.. but I'm not sure if I copied it down right..
The answer that I copied down was
9[square root of 3]/2 + i9[square root of 3]/2..

That answer would like like it would come from a 45deg thing.. but sinn and cosn are 60degs..

Just making sure.. So has anyone seen where I went wrong?
 
Last edited:

Answers and Replies

  • #2
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looks to be copied down wrong.
Just don't use decimals, write 9/2, not 4.5
 
  • #3
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I edited my initial post since I forgot the imaginary "i" part. And yes, I realize that 9/2 is 4.5. Anyone else NOT get 4.5[square root of 3] as opposed to just plain old 4.5 (9/2) for the "real" part?
 
  • #4
cristo
Staff Emeritus
Science Advisor
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You copied the answers down incorrectly. The correct answer is [tex]w^2=\frac{9}{2}+i\frac{9\sqrt{3}}{2}[/tex].
 
  • #5
118
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Thanks!
:-)
 

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