- #1
khfrekek92
- 88
- 0
Hi everyone!
I am trying to create the density matrix for a spin-1/2 particle that is in thermal equilibrium at temperature T, and in a constant magnetic field oriented in the x-direction. This is a fairly straightforward process, but I'm getting stuck on one little part.
Before starting I need to find the energy eigenvalues (In order to find the partition function):
H=-μS⋅B=-μBσ_x
But since σ_x is an off-diagonal matrix (unlike σ_z), plugging this Hamiltonian into the Schrodinger Equation yields two equations (By letting |ψ>=(ψ1,ψ2))
Eψ1=-μBψ2
Eψ2=-μBψ1
And then solving these like normal for E gives us only one energy eigenstate for this system (with degeneracy 2):
E=μB
However, when the magnetic field was in the z direction, the z pauli spin matrix was diagonal and didn't switch the positions of ψ1 and ψ2, which gave me two energy eigenstates (±μB).
So my question is, why would a magnetic field in the x-direction NOT break the degeneracy of the energy eigenstates, while in the z-direction it does? These directions are completely arbitrary and should yield the same results, right?
Thanks
I am trying to create the density matrix for a spin-1/2 particle that is in thermal equilibrium at temperature T, and in a constant magnetic field oriented in the x-direction. This is a fairly straightforward process, but I'm getting stuck on one little part.
Before starting I need to find the energy eigenvalues (In order to find the partition function):
H=-μS⋅B=-μBσ_x
But since σ_x is an off-diagonal matrix (unlike σ_z), plugging this Hamiltonian into the Schrodinger Equation yields two equations (By letting |ψ>=(ψ1,ψ2))
Eψ1=-μBψ2
Eψ2=-μBψ1
And then solving these like normal for E gives us only one energy eigenstate for this system (with degeneracy 2):
E=μB
However, when the magnetic field was in the z direction, the z pauli spin matrix was diagonal and didn't switch the positions of ψ1 and ψ2, which gave me two energy eigenstates (±μB).
So my question is, why would a magnetic field in the x-direction NOT break the degeneracy of the energy eigenstates, while in the z-direction it does? These directions are completely arbitrary and should yield the same results, right?
Thanks