Density Matrix for Spin 1/2 particle in a magnetic field

khfrekek92
Messages
79
Reaction score
0
Hi everyone!

I am trying to create the density matrix for a spin-1/2 particle that is in thermal equilibrium at temperature T, and in a constant magnetic field oriented in the x-direction. This is a fairly straightforward process, but I'm getting stuck on one little part.

Before starting I need to find the energy eigenvalues (In order to find the partition function):

H=-μS⋅B=-μBσ_x

But since σ_x is an off-diagonal matrix (unlike σ_z), plugging this Hamiltonian into the Schrödinger Equation yields two equations (By letting |ψ>=(ψ1,ψ2))

Eψ1=-μBψ2
Eψ2=-μBψ1

And then solving these like normal for E gives us only one energy eigenstate for this system (with degeneracy 2):

E=μB

However, when the magnetic field was in the z direction, the z pauli spin matrix was diagonal and didn't switch the positions of ψ1 and ψ2, which gave me two energy eigenstates (±μB).

So my question is, why would a magnetic field in the x-direction NOT break the degeneracy of the energy eigenstates, while in the z-direction it does? These directions are completely arbitrary and should yield the same results, right?

Thanks
 
Physics news on Phys.org
You have made a mistake. Your equations lead to ##E^2=(\mu B)^2##, which has two solutions.
 
Ah man such a small algebra error! That makes everything work out perfectly, duh! Thank you so much!
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K