Density. Please explain this solution

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SUMMARY

The problem involves calculating the density of a sphere submerged in water, tethered to the bottom with a string. The tension in the string is established as one-third the weight of the sphere. The solution requires understanding the relationship between the weight of the sphere, the weight of the water displaced, and the volume of the sphere, which is given by the formula (4/3)πr³. The key equations are derived from the principles of buoyancy and tension in fluids.

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  • Ability to interpret tension in fluid mechanics
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Homework Statement


A sphere completely submerged in water is tethered to the bottom with a string. The tension in the string is one-third the weight of the sphere.

What is the density of the sphere


Homework Equations



Here is the solution to this problem. It is problem 15.17, the second one on the page. I understand the first line, but for the second line of equations, I have no idea where these equations are coming from. Can someone please explain the second line of equations?
http://www.phy-astr.gsu.edu/Hsiao-Ling/Homework10.pdf

The Attempt at a Solution



Solution is in the link, just need help understanding it
 
Last edited by a moderator:
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They are mostly about the volume of a sphere.
The tension in the string = weight of sphere - weight of water displaced
The weight of the water is = volume of water * density of water * g
The volume is found from the volume of a sphere ( 3/4 pi r^3 )
 

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