Derivate of generalized function

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SUMMARY

The discussion centers on the derivation of the relationship between the derivative of a generalized function and integration by parts. Specifically, it establishes that if the derivative f'(x) of a generalized function f(x) is represented by the sequence f'_n(x), then the equation ∫_{-∞}^{∞} f'(x) F(x) dx = - ∫_{-∞}^{∞} f(x) F'(x) dx holds true. The confusion arises regarding the origin of the negative sign in the equation, which is clarified through the application of integration by parts, leading to the conclusion that ∫ f' F dx = -∫ f F' dx when extended to generalized functions.

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greisen
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Hi,

I have to show that if the derivate f'(x) of a generalized function f(x) is defined by the sequence f'_n(x) where f(x) is defined

[tex]f_n(x)[\tex] <br /> <br /> then <br /> <br /> [tex]\int_{-\infty}^{\infty}f'(x)F(x) dx = - \int_{-\infty}^{\infty}f(x)F'(x) dx[/tex]<br /> <br /> I use the limits for generalized functions and get<br /> <br /> [tex]lim_{n \to \infty} \int_{-\infty}^{\infty}f'_n(x)F(x) dx = - \int_{-\infty}^{\infty}f_n(x)F'(x) dx[/tex]<br /> <br /> which should show the above - I am a liltte confused where the minus sign comes from?<br /> [tex]- \int_{-\infty}^{\infty}f(x)F'(x) dx[/tex]<br /> <br /> Any help appreciated - thanks in advance[/tex]
 
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it is from integration by parts
let f,F be functions
d(fF)=(fF)'dx=f'Fdx+fF'dx
f'Fdx=d(fF)-fF'dx
integrating gives (assume f,F->0)
ʃf'Fdx=ʃd(fF)-ʃfF'dx
ʃd(fF)=0 so
ʃf'Fdx=-ʃfF'dx
now extent this to generalized functions by limits
 

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