Derivating a velocity's components

  • Thread starter Thread starter soopo
  • Start date Start date
  • Tags Tags
    Components
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 2K views
soopo
Messages
222
Reaction score
0

Homework Statement



What is the derivate of the following equation?

[tex]v(t) = \dot{r}\hat{r} + r \dot{\hat{r}} = \dot{r} \hat{r} + r \dot{\delta} \hat{e}[/tex]

where e is dependent on the angle, delta.

The Attempt at a Solution



My answer:

We know that
[tex]\hat{r} = \frac {r} {|r|}[/tex]

=> [tex]\hat{r} = \frac {r} {|r|}[/tex]

=> [tex]D( \dot{r} \hat{r} ) = \ddot{r} \hat{r} + \dot{r} \dot{ \hat{r}}[/tex]
=> [tex]D( r \dot{\hat{r}} ) = \dot{r} \dot{\hat{r}} + \frac {r \ddot{r} } {|r|}[/tex]

so we get

[tex]a(t) = \hat{r} ( \ddot{r} ) + 2 \dot{r} \dot{ \hat{r}} + \frac {r \ddot{r}} {|r|}[/tex]

which is wrong.

The correct answer is

[tex]\dot{v(t)} = (\ddot{r} - r \dot{\delta}^2) \hat{r} + (r \ddot{\delta} + 2\dot{r} \dot{\delta}) \hat{e}[/tex]
 
Physics news on Phys.org
Are you working with vectors or scalars?
 
foxjwill said:
Are you working with vectors or scalars?

The derivate of a vector is a vector.
It consists of unit vectors which means that there is too scalars in the unit vectors.
So I am working with vectors.