Derivation of angle of deviation in a prism

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The discussion focuses on deriving the angle of deviation (D) in a prism using the angles of incidence (\theta_a), refraction (\theta_g), and the prism angle (A). The equation (\theta_a - \theta_g) + (\theta_a' - \theta_g') = D is central to this derivation. Participants express difficulty in substituting \theta_a' into the required terms for the derivation. Additionally, it is noted that the refractive index can be calculated from the angles \theta_a and \theta_g. The conversation emphasizes the mathematical relationships necessary for understanding the angle of deviation in a prism.
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derivation of an expression for the angle of deviation in a prism, in terms of \thetaa and \thetag and A


Homework Equations


(\thetaa - \thetag ) + (\thetaa' - \thetag' ) = D

A = \thetag + \thetag'

i get stuck trying to put \thetaa' into the terms the question states, anyone have an idea? thanks,
 
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You can work out the refractive index from \theta_a and \theta_g.
 
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