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Sumedh
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Electric potential is the work done in moving a unit charge from infinity to a point in an electric field.
Electric potential due to point charge:
[itex]V=-\int \vec{E}\cdot d\vec{s}[/itex]
[itex]V=-\int E\cdot ds cos \vartheta[/itex]
if the stationary charge is positive and
if the test charge is is moved from infinity to point P
then
[itex]V=-\int E\cdot ds cos 180[/itex]
[itex]V=-KQ \int \frac {1}{r^2} ds cos 180[/itex]
now how to solve further
as stationary charge is positive the electric field is outward i.e. from p to infinity
and movement of charge is from infinity to P
specially the signs and the direction of the field and the direction of ds
and definite integration from P to infinity or from infinity to P?
please give some imaginary picture or idea of how the test charge moves
I am confused with it please help.
Electric potential due to point charge:
[itex]V=-\int \vec{E}\cdot d\vec{s}[/itex]
[itex]V=-\int E\cdot ds cos \vartheta[/itex]
if the stationary charge is positive and
if the test charge is is moved from infinity to point P
then
[itex]V=-\int E\cdot ds cos 180[/itex]
[itex]V=-KQ \int \frac {1}{r^2} ds cos 180[/itex]
now how to solve further
as stationary charge is positive the electric field is outward i.e. from p to infinity
and movement of charge is from infinity to P
specially the signs and the direction of the field and the direction of ds
and definite integration from P to infinity or from infinity to P?
please give some imaginary picture or idea of how the test charge moves
I am confused with it please help.
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