Electric potential is the work done in moving a unit charge from infinity to a point in an electric field.(adsbygoogle = window.adsbygoogle || []).push({});

Electric potential due to point charge:

[itex]V=-\int \vec{E}\cdot d\vec{s}[/itex]

[itex]V=-\int E\cdot ds cos \vartheta[/itex]

if the stationary charge is positive and

if the test charge is is moved from infinity to point P

then

[itex]V=-\int E\cdot ds cos 180[/itex]

[itex]V=-KQ \int \frac {1}{r^2} ds cos 180[/itex]

now how to solve further

as stationary charge is positive the electric field is outward i.e. from p to infinity

and movement of charge is from infinity to P

specially the signs and the direction of the field and the direction of ds

and definite integration from P to infinity or from infinity to P?

please give some imaginary picture or idea of how the test charge moves

I am confused with it please help.

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# Derivation of electric potential due to point charge

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