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TrippingBilly

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http://filesaur.us/files/1858/pulley/

Derivation of equation for mass on pulley and displacement

Sorry that the picture stinks, but its all I got. The system is in equilibrium.The counter mass on the left is mass A and the mass on the right is mass B, both of mass m. The center mass of mass M is denoted as B. The length of the system is denoted as L. h stands for the vertical displacement of the center mass. The equation is..

h= ML / sqrt(16m^2 - 4M^2)

I wrote the equations for the sum of the forces and my teacher told me I could derive it from those but I can't get any further than what I have.

Forces in x direction = T(sub c)cos(theta) - T(sub a)cos(theta) =0 and

Forces in y direction = T(sub c)sin(theta) + T(sub a)sin(theta) - T(sub b) = 0

Derivation of equation for mass on pulley and displacement

Sorry that the picture stinks, but its all I got. The system is in equilibrium.The counter mass on the left is mass A and the mass on the right is mass B, both of mass m. The center mass of mass M is denoted as B. The length of the system is denoted as L. h stands for the vertical displacement of the center mass. The equation is..

h= ML / sqrt(16m^2 - 4M^2)

I wrote the equations for the sum of the forces and my teacher told me I could derive it from those but I can't get any further than what I have.

Forces in x direction = T(sub c)cos(theta) - T(sub a)cos(theta) =0 and

Forces in y direction = T(sub c)sin(theta) + T(sub a)sin(theta) - T(sub b) = 0

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