Derivation of imaginary exponential function

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The discussion focuses on deriving the imaginary exponential function, specifically exp(-ik1r) using Taylor expansion based on exp(-ik0r). The expansion converges for lower values of r (0.3 - 1.2) but fails for larger values (100-1000), raising questions about the convergence behavior. A participant suggests that proving e^{\theta\cdot i}=cis(θ) is sufficient for deriving the imaginary exponential function, without needing to handle the k variables. They mention using differential equations to demonstrate the relationship and convergence of the functions. The conversation highlights the challenges of applying Taylor expansion for larger r values in this context.
vinh pham
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I would like to find derivations of exp(-ik0r) respect to k in order to calculate exp(-ik1r) by using Taylor expansion:

exp(-ik1r) = (exp(-ik0r))(0) +(k1 -k0)(exp(-ik0r))(1)/1! + (k1 -k0)2(exp(-ik0r))(2)/2! + ...

This expansion converges when the value of r is relative low (0.3 - 1.2). However, when r grows with larger value (100-1000), the expansion does not converge any more.

k0 = 21
k1 = 27

Is there any solution to find exp(ik1r) by using Taylor expansion for larger r?

Thank you very much
 
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How do you know that for large r, it doesn't converge anymore? Early terms start to get larger, but how do you know that later ones also do?

Anyways, all you need for derivation of imaginary exponential function is proving that e^{\theta\cdot i}=cis\left(\theta\right), none of these nasty k's, I think. Quite easily provable by substituting into the taylor expansion for exp, and similarly provable that it converges. I originally proved it, actually, with differential equations, noting that \dfrac{\exp'}{\exp}=\dfrac{cis'}{cis}=i and proving that they differ by a constant, and plugging in 0 gives us the desired.
 

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