Derivation of Law of Refraction

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SUMMARY

The law of refraction, expressed as n = sinI/sinR, defines the refractive index (n) in relation to the angles of incidence (I) and refraction (R). The discussion emphasizes that the ratio involves sine functions rather than direct angle comparison due to the underlying principles of trigonometry. Key derivations can be traced back to Fermat's principle and Hamilton's principle, which focus on the velocity components parallel to the surface. Additionally, practical examples, such as the 'running along the sand--swimming across the river' analogy, illustrate the law's application.

PREREQUISITES
  • Understanding of basic trigonometry, specifically sine functions.
  • Familiarity with the concepts of refractive index and light behavior.
  • Knowledge of Fermat's principle and Hamilton's principle in optics.
  • Ability to interpret geometric representations of physical laws.
NEXT STEPS
  • Explore the derivation of Snell's Law using Fermat's principle.
  • Study Hamilton's principle and its applications in optics.
  • Investigate geometric interpretations of light refraction.
  • Learn about practical applications of the refractive index in various materials.
USEFUL FOR

Students of physics, optics researchers, and educators seeking to deepen their understanding of light behavior and refraction principles.

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Hello;

I have learned that the law of refraction is n = sinI/sinR, where n is the refractive index, I is the angle of incidence, and R is the angle of refraction.

But why is it sinI/sinR, and not simply angle I/angle R if it is identifying the ratio between the two angles?

I have heard that I need to do some trigonometric manipulation but I don't know what this manipulation is. Thanks.

(i.e. if I = 60 degrees, and R = 30 degrees, then the refractive index is sqrt(3), not 2... but why? how was this law derived?)
 
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You can derive it from Fermat's principle (least time), or from hamilton's principle. The key is that it only depends on the component of velocity parallel to the surface.
There is also the old, 'running along the sand--swimming across the river' in the least time example which gives you the same result.
 
Hello;

Apologies for the delay between replies; I have no internet access so I have to wander around the street looking for hotspots. Thanks for the link - it helped me formulate a way to geometrically show why Snell's Law is true. I also found this, which helped too: http://farside.ph.utexas.edu/teaching/316/lectures/node128.html
 

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