Derivation of Lorentz Time Transformation

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SUMMARY

The discussion focuses on deriving the Lorentz time transformation using the equations for gamma and the Lorentz space transformation. The participant references the equation x' = (x - vt) / √(1 - v²/c²) and its counterpart x = (x' + vt') / √(1 - v²/c²). An arithmetic error was identified in the derivation process, which, once corrected, allows for expressing t' in terms of x and t. This highlights the importance of accurate algebraic manipulation in physics derivations.

PREREQUISITES
  • Understanding of Lorentz transformations
  • Familiarity with the concept of gamma (γ) in special relativity
  • Basic algebra skills for manipulating equations
  • Knowledge of the speed of light (c) and its significance in relativity
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  • Study the derivation of Lorentz transformations in detail
  • Learn about the implications of gamma (γ) in time dilation
  • Explore applications of Lorentz transformations in modern physics
  • Investigate common algebraic mistakes in physics derivations
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Students of physics, educators teaching special relativity, and anyone interested in the mathematical foundations of relativistic concepts.

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Homework Statement
Derive the Lorentz Time Transformation
Relevant Equations
g (I am using g instead of gamma)=1/sqrt(1-v^2/c^2)
x'=(x-vt)/sqrt(1-v^2/c^2)
I have to derive the Lorentz time transformation given the equation for gamma and the equation for the Lorentz space transformation.
I started by using relevant equations from the Space derivation done in class (also the one that Ramamurti Shankar does). Here is a picture of what I have tried. (Yes, I am using g instead of gamma).
 

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You've made an arithmetic slip between the bottom of the first column and the top of the second. Correct that and it should come out right.
 
Last edited:
On the white board you write
x'=\frac{x-vt}{\sqrt{1-v^2/c^2}}
So you can expect by relativity with changing v to -v,
x=\frac{x'+vt'}{\sqrt{1-v^2/c^2}}
It enables you to express t' by x and t.
 
I spotted my algebraic mistake! Thank you so much!
 

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