Derivative Help with f(x)= 1/x +1/(x+1)

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Homework Help Overview

The original poster is working on differentiating the function f(x) = 1/x + 1/(x+1). They express uncertainty in reaching the correct derivative, which they believe to be -1/x² - 1/(x+1)².

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Some participants suggest that the original poster is overcomplicating the differentiation process and recommend differentiating each term separately. Others propose rewriting the function using exponents to simplify the differentiation.

Discussion Status

Participants are exploring different methods for differentiating the function, with some providing guidance on simplifying the approach. There is no explicit consensus on the best method, but various interpretations of the differentiation process are being discussed.

Contextual Notes

There is a mention of a potential misunderstanding regarding terminology, as one participant points out the use of "derivate" instead of "differentiate." Additionally, there is a note that calculus-related questions may not be appropriate for this forum.

helppleasemath
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Homework Statement


[/B]
I have to derivate f(x)

f(x) = 1/x +1/(x+1)

Answer is = -1/x2 - 1/(x+1)2
I can't seem to get to that answer :(

thank you

Homework Equations

The Attempt at a Solution


f(x) = (1/x +1/(x+1))'
= (2x+1)/x(x+1)' = ((2x+1)' * (x(x+1)-(2x+1)*(x(x+1)')/x2(x+1)2
=(2(x(x+1)-(2x+1)*(x(1)+(x+1))/x2(x+1)2
=(2x(x+1)-(2x+1)*(2x+1))/x2(x+1)2
=2(x(x+1))-(2x+1)2/x2(x+1)2
 
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It seems to me that you are doing a bunch of extra work. You don't need to combine the terms over a common denominator to evaluate the derivative because the derivative of a sum is simply the sum of the derivatives.

Differentiate each term separately. If it helps, rewrite the terms with exponents instead of having them as fractions (i.e. write 1/x as x-1)
 
Try re-writing ##f(x)## as ##f(x)=x^{-1} + (x+1)^{-1}##. From here you can use the chain rule on the second term.
 
helppleasemath said:

Homework Statement


[/B]f(x) = 1/x +1/(x+1)

Answer is = -1/x2 - 1/(x+1)2
I can't seem to get to that answer :(

thank you

Homework Equations

The Attempt at a Solution


f(x) = (1/x +1/(x+1))'
= (2x+1)/x(x+1)' = ((2x+1)' * (x(x+1)-(2x+1)*(x(x+1)')/x2(x+1)2
=(2(x(x+1)-(2x+1)*(x(1)+(x+1))/x2(x+1)2
=(2x(x+1)-(2x+1)*(2x+1))/x2(x+1)2
=2(x(x+1))-(2x+1)2/x2(x+1)2
You actually didn't post a question but from the answer given, the function was differenciated, which is calculus and therefore shouldn't be posted here.
 
@helppleasemath, minor point, but there is no such word in English as "derivate" at least in the context of calculus. The word you want is "differentiate", the action you perform to get the derivative.
 
Mark44 said:
@helppleasemath, minor point, but there is no such word in English as "derivate" at least in the context of calculus. The word you want is "differentiate", the action you perform to get the derivative.
oh ok sorry wasnt sure what word to use lol.
 

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