Derivative of 101-x2 using Chain Rule - Calculus I Explained

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Find the derivative of 101-x2.

1.) So, I used power rule to get: (1-x2)(10-x2).
2.) Then I did chain rule and multiplied my previous answer with (d/dx)(-x2).
3.) The answer I get is: (-2x)(1-x2)(10-x2).


When I use my calculator, the answer I get is: -20*ln(10)*10-x2. So, where does -20*ln(10) come from?
 
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The power rule applies when ##x## is the base, not in the exponent. What kinds of functions are the derivatives of the exponential function?
 
You have to use the formula for a constant to a variable exponent..

a^u = lna (u) (u')

So you use properties of exponents to get 10 times 10 to the power of negative x squared..

So that's a constant with a variable exponent..

So you get 10(ln10)(10^-x^2)(-2x)
^u ^u'
Then that simplifies to your answer, but you forgot the x.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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