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## Homework Statement

f(x)=(x^3)+x. If h(x) is the inverse of f(x), find h'(2).

## Homework Equations

(F[tex]^{-1}[/tex])'(x)=[tex]\frac{1}{F'(F^{-1}x)}[/tex]

## The Attempt at a Solution

I want to find h'(2)=(F[tex]^{-1}[/tex])'(2)=[tex]\frac{1}{F'(F^{-1}(2))}[/tex]

I know f'(x)=3(x^2)+1, so I just need to find h(2), but I don't know how to solve f(x)=(x^3)+x for its inverse. Is it possible to solve for x and then switch x and y with this type of function?