Derivative of c= (2p/q)-1/2: Step-by-Step Solution and Tips

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SUMMARY

The discussion focuses on finding the derivatives dc/dp and dc/dq for the equation c = (2p/q) - 1/2. The correct derivatives are dc/dp = -1/2 * (2p/q)^(-3/2) * (2/q^2) and dc/dq = -1/2 * (2p/q)^(-3/2) * (-2p/q^2). Participants highlighted the importance of correctly applying the chain rule in differentiation to achieve accurate results.

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Homework Statement



Find dc/dp and dc/dq.

Homework Equations



c= (2p/q)-1/2

The Attempt at a Solution



I just want to make if I'm right. I got...
dc/dp = (2/q)-1/2

dc/dq = [-2p/(q^2)] -1/2

Thanks.
 
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Hi,
There is an error in your use of the chain rule:
[tex]\frac{dc}{dp}=-\frac{1}{2}\left(\frac{2p}{q}\right)^{-\frac{3}{2}}\cdot\left(\frac{2q-0}{q^2}\right)[/tex]
then simplify.

Same thing for dc/dq:
[tex]\frac{dc}{dq}=-\frac{1}{2}\left(\frac{2p}{q}\right)^{-\frac{3}{2}}\cdot\left(\frac{0-2p}{q^2}\right)[/tex]
then simplify.
 
Last edited:

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