# Homework Help: Derivative of function using evaluation theorem

1. May 8, 2010

### TsAmE

1. The problem statement, all variables and given/known data

Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function:

y = ∫ 0 to tanx ( ( t + (t)^1/2 )^1/2

2. Relevant equations

None

3. The attempt at a solution

I got my final answer to be:

y' = ( ( tanx + (tanx)^1/2 )^1/2

y' = ( ( tanx + (tanx)^1/2 )^(1/2) * (secx)^2

2. May 8, 2010

### vela

Staff Emeritus
Hint: Chain rule.

3. May 9, 2010

### TsAmE

My lecturer hasnt said anything about chain rule yet. Is there another normal way to do it? If not, could you please explain how to use the chain rule with it?

4. May 9, 2010

### vela

Staff Emeritus
Let F(t) is an antiderivative of $$\sqrt{t+\sqrt{t}}$$. Express

$$y=\int_0^{\tan x} \sqrt{t+\sqrt{t}}\,dt$$

in terms of F(t). Then differentiate it to find y'(x). When you take this derivative, you'll need to use the chain rule.

5. May 10, 2010

### TsAmE

But if you differentiate that integral you will get $$\sqrt{t+\sqrt{t}}$$ before subing in 0 and tanx, I am not sure how you would do chain rule in reverse

6. May 10, 2010

### Staff: Mentor

If this were your equation, you would be correct.
$$y=\int_0^x \sqrt{t+\sqrt{t}} dt$$
For this equation
$$dy/dx = \sqrt{x+\sqrt{x}}$$

The trouble is, your integral is not from 0 to x, but is instead from 0 to tan(x). The idea with the fundamental theorem of calculus is that
$$d/dx \int_a^x f(t) dt = f(x)$$

What you have is
$$d/dx \int_a^{g(x)} f(t) dt = f(x)$$

They're not the same, and you need to use the chain rule for your problem. Note that your problem is NOT about finding the antiderivative of your integrand, and then substituting in tan(x) and 0.

7. May 10, 2010

### vela

Staff Emeritus
The reason I suggested you write y(x) in terms of F(t) first and then differentiate it is to avoid the mistake you keep making. The fundamental theorem of calculus tells you

y(x) = F(tan x) - F(0)

Do you now see why you have to use the chain rule?