(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the derivative:

y=sec^{-1}(1/2t^{3})

2. Relevant equations

[tex]\frac{\frac{du}{dx}}{|u|\sqrt{u^2-1}}[/tex]

3. The attempt at a solution

I have an example to follow, but I dont know how step 1. became step 2.?...or more exactly the last part under the radical? (1-4t^6) instead of just -1 ???

1.[tex]y'=\frac{\frac{-3}{2t^4}}{|\frac{1}{2t^3}|\sqrt{(\frac{1}{2t^3})^2-1}}[/tex]

2.[tex]y'=\frac{-3}{(t)\sqrt{\frac{1}{4t^6}(1-4t^6)}}[/tex]

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Derivative of inverse trig functions.

**Physics Forums | Science Articles, Homework Help, Discussion**