(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Find the derivative:

y=sec^{-1}(1/2t^{3})

2. Relevant equations

[tex]\frac{\frac{du}{dx}}{|u|\sqrt{u^2-1}}[/tex]

3. The attempt at a solution

I have an example to follow, but I dont know how step 1. became step 2.?...or more exactly the last part under the radical? (1-4t^6) instead of just -1 ???

1.[tex]y'=\frac{\frac{-3}{2t^4}}{|\frac{1}{2t^3}|\sqrt{(\frac{1}{2t^3})^2-1}}[/tex]

2.[tex]y'=\frac{-3}{(t)\sqrt{\frac{1}{4t^6}(1-4t^6)}}[/tex]

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# Derivative of inverse trig functions.

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