Derivative of kinectic energy , dK/dv

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SUMMARY

The derivative of kinetic energy (Ek) with respect to velocity (v) is defined as mv, which represents linear momentum. This relationship arises from the principles of Newtonian physics, where the laws remain consistent across inertial frames. The discussion highlights the connection between kinetic energy, momentum, and force, emphasizing that force is the derivative of momentum and work is the product of force and distance. For a comprehensive understanding, readers are directed to a detailed derivation available in the linked forum thread.

PREREQUISITES
  • Understanding of basic calculus concepts, specifically derivatives.
  • Familiarity with the formula for kinetic energy: Ek = 1/2mv².
  • Knowledge of Newtonian mechanics and the concept of momentum.
  • Basic comprehension of the relationship between force, work, and energy.
NEXT STEPS
  • Study the principles of Newtonian Relativity and its implications on momentum conservation.
  • Explore the derivation of kinetic energy and its relationship with momentum in detail.
  • Learn about the concept of force as the derivative of momentum.
  • Investigate the differences between Newtonian and Einsteinian energy and momentum in Minkowski space.
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Students in physics or mathematics, particularly those studying calculus and mechanics, as well as educators seeking to explain the relationship between kinetic energy and momentum.

c77793
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i'm in my freshman year and I'm starting to learn Derivatives in Calculus, and I was wondering, once Ek (kinectic energy) = 1/2mv², then, the derivative of Ek in term of velocity would be mv, which is equal to the linear momentum... I'm finding hard to understand the idea that the variation of Kinect over a variable velocity is the linear momentum...can someone explain me this in a didactic way? I was just playing around deriving physics formulas haha
 
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hi c77793! :smile:
c77793 said:
I'm finding hard to understand the idea that the variation of Kinect over a variable velocity is the linear momentum...can someone explain me this in a didactic way?

it's because of Newtonian Relativity

the (Newtonian) laws of physics are the same in any inertial frame​

suppose you have bodies with ∑miui2 = ∑mivi2 in one frame

now choose another frame with relative velocity w in the k-direction …

∑mi(ui - wk).(ui - wk) = ∑mi(vi - wk).(vi - wk)
cancelling (and dividing by 2) gives us …

w∑miui.k = w∑mivi.k

since w is arbitrary, we can divide by w, and get conservation of momentum in in the k direction

however, instead of cancelling, we could have differentiated wrt w (in other words, exploiting the translational symmetry of Newtonian space), giving …

w∑mi(ui - wk).k = w∑mi(vi - wk).k

(and then cancelled, giving the same result)

(btw, this also works with Einsteinian energy and momentum, in Minkowski space)
 
c77793 said:
i'm in my freshman year and I'm starting to learn Derivatives in Calculus, and I was wondering, once Ek (kinectic energy) = 1/2mv², then, the derivative of Ek in term of velocity would be mv, which is equal to the linear momentum... I'm finding hard to understand the idea that the variation of Kinect over a variable velocity is the linear momentum...can someone explain me this in a didactic way? I was just playing around deriving physics formulas haha

Well I was also wondering about that and I can't still find the physical relationship between the two, however both are related to force (since force is the derivative of momentum and work is (force)(distance)).
The complete derivation you can find in this thread https://www.physicsforums.com/showthread.php?t=68682
 

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