Derivative Techniques: nx^n-1 and k^x ln k

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Homework Help Overview

The discussion revolves around understanding the differentiation techniques for two types of functions: exponential functions like \(2^x\) and power functions like \(x^\pi\). Participants are examining the appropriate application of the derivative rules for these distinct function types.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the differentiation of \(2^x\) and \(x^\pi\), questioning why different rules apply to each. There is a discussion on the nature of the functions, with some suggesting that the power rule is misapplied in the case of \(2^x\). Others propose expressing \(2^x\) in a different form to apply the derivative rules correctly.

Discussion Status

The conversation is ongoing, with participants providing insights into the differences between exponential and power functions. Some guidance has been offered regarding the correct application of differentiation rules, but there is no explicit consensus on the best approach yet.

Contextual Notes

Participants note that the differentiation rules have specific conditions under which they apply, particularly emphasizing the distinction between the variable being in the exponent versus the base. There is also mention of the limitations of the power rule in certain contexts.

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Homework Statement



Let's take two problems, the derivative of

2x

and

xπ

For the second one the book says that answer is

πxπ-1

Well if you can do that for the above, then why not for the first problem?

The book gives the answer to the first problem as

2x ln 2

why not x2x-1?

essentially what i need to know for finding derivatives, there are two techniques.
1. nx^n-1
2. k^x ln k

when do I use which technique?
 
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bobsmith76 said:

Homework Statement



Let's take two problems, the derivative of

2x

and

xπ

For the second one the book says that answer is

πxπ-1

Well if you can do that for the above, then why not for the first problem?

The book gives the answer to the first problem as

2x ln 2

why not x2x-1?

essentially what i need to know for finding derivatives, there are two techniques.
1. nx^n-1
2. k^x ln k

when do I use which technique?

Because that rule only works when the power of the x term is a constant (independent of x).

To differentiate 2x, express it as exln(2). This is of the form ekx, where k is a constant.
 
it makes a BIG difference whether x is "upstairs" (in the exponent), or "downstairs" (being exponentiated).

if you go back to the definition:

d(2x)/dx = limh→0 (2(x+h)-2x)/h

you can see that you're not going to get an easy way to simplify.

basically, e is the "natural base" for exponential functions, and other bases have logarithms as a "conversion factor":

2x = (eln(2))x = eln(2)x

which is of the form eax, so has derivative aeax, by the chain rule.
 
2x and xn are very different types of functions. The first is an exponential function, so called because the variable is in the exponent. The second is a power function, so called because the variable is in the base, which is raised to a fixed power.

There is no single differentiation rule, other than the definition, that covers both of these functions. You are misusing the power rule to conclude that d/dx(2x) = x2x-1. Each of the rules has "fine print" that says when it can be applied. Read the fine print.
 

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