Derivatives and Chain Rule: Solving for x and y

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SUMMARY

The discussion focuses on the application of the chain rule in calculus, specifically in the context of the relationship between the variables x and y defined by x = e^t and y(x(t)) = Y(t). The key conclusion is that the expression x(dy/dt)(dt/dx) can be transformed into dY/dt by recognizing that dy/dt = (dy/dx)(dx/dt), leading to the simplification x(dy/dx) = e^t(dy/dx). This highlights the importance of understanding the derivative of the exponential function in relation to the chain rule.

PREREQUISITES
  • Understanding of calculus concepts, particularly the chain rule.
  • Familiarity with derivatives of exponential functions.
  • Knowledge of function notation and variable substitution.
  • Basic proficiency in solving differential equations.
NEXT STEPS
  • Study the chain rule in detail, focusing on its applications in calculus.
  • Learn about derivatives of exponential functions, specifically e^t.
  • Explore variable substitution techniques in calculus problems.
  • Practice solving differential equations involving exponential functions.
USEFUL FOR

Students studying calculus, particularly those tackling problems involving derivatives and the chain rule, as well as educators looking for examples to illustrate these concepts.

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Homework Statement



let x=et and define y(x(t))=Y(t)

Show that x(d/dx)y=(d/dt)Y

Homework Equations



n/a

The Attempt at a Solution



i try using chain rule but

x(dy/dt)(dt/dx) and i don't know how to make it to be dY/dt, and i don't have clue what is the point of x=et.. help T_T
 
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Look at it the other way around. If [itex]x= e^t[/itex] then [itex]dy/dt= (dy/dx)(dx/dt)= e^t(dy/dx)= x(dy/dx)[/itex]. The point of "[itex]x= e^t[/itex] is that the derivative of [itex]x= e^t[/itex] is [itex]x= e^t[/itex].
 


my goodness, thank you very very very much
 

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