Derivatives of a Constant in a Trigonometric Function

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SUMMARY

The discussion focuses on finding the second derivative, y'', of the function y = (1/3)(1 + cos²(√x)). The first derivative, y' = (1/3)(cos(√x)(-sin(√x))(1/√x)), was confirmed as correct by the instructor. It is established that constants can be factored out during differentiation, allowing the constant (1/3) to be disregarded when calculating derivatives. This principle is affirmed with the example y = a*f(t), where the derivative dy/dt equals a*df/dt.

PREREQUISITES
  • Understanding of basic calculus concepts, specifically differentiation.
  • Familiarity with trigonometric functions and their derivatives.
  • Knowledge of the chain rule in calculus.
  • Ability to manipulate constants during differentiation.
NEXT STEPS
  • Review the chain rule in calculus for differentiating composite functions.
  • Practice finding derivatives of trigonometric functions, particularly involving constants.
  • Explore the application of the product rule in differentiation.
  • Study higher-order derivatives and their significance in calculus.
USEFUL FOR

Students studying calculus, particularly those focusing on differentiation of trigonometric functions and constants, as well as educators teaching these concepts.

Jani08
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Homework Statement



Find y'' if y=1/3(1+cos^2(√x))

Homework Equations





The Attempt at a Solution



Now I believe I got the first derivative right since the teacher marked ir right, but my real question here is what do I do with the 1/3? Is it ok to throw away the constant when I see derivative and just worry bout the other the thing in the parenthesis?

y'=1/3(cox√x)(-sin√x)(1/√x)
y''=??
 
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Yes, it is ok.
 
if a is a constant
y=a*f(t)
then
dy/dt=a*df/dt
 

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