Derivatives of arctan((x+y)/(1-xy))

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SUMMARY

The discussion focuses on finding all second partial derivatives of the function z = arctan((x+y)/(1-xy)). The user initially attempts to compute the first derivative using the formula d/dx of arctan(x) = 1/(1+x^2) but expresses uncertainty about the correctness of their approach. A suggestion is made to simplify the function using the addition formula for tangent, tan(α+β) = (tan(α)+tan(β)/(1-tan(α)tan(β)). Additionally, guidance is provided on using advanced math notation for clearer presentation of equations.

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  • Understanding of partial derivatives
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  • Knowledge of the addition formula for tangent
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Students studying calculus, particularly those focusing on multivariable functions and derivatives, as well as educators looking for effective ways to present mathematical equations online.

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Homework Statement



Find all second partial derivatives of
z=arctan((x+y)/(1-xy))

Homework Equations



d/dx of arctan(x) is 1/(1+x^2)

The Attempt at a Solution



Not sure how to proceed... I don't want the answer, just an idea as to how to move forward.

My attempt at finding the first derivative...

z'=(1/(1+(x+y/(1-xy)) * (x(1-xy) - (x+y(-y)) / (1-xy)^2

Is this correct? If it is, I honestly don't know how to find the second derivative...

On another note, can someone tell me how I can use math notation instead of plain text, to make the equations and such easier to read? Thanks guys.
 
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Take care of the parentheses. Check the derivative of the arctan function.

To make your task easier, remember the addition formula :
[tex]tan(\alpha+\beta)=\frac{tan(\alpha)+tan(\beta)}{1-tan(\alpha)tan(\beta)}[/tex]
Can you write the function z(x,y) in a simpler form?
As for Math notations, go to "advanced" and click on the 'Σ'.
ehild
 

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