Deriving a formula for KE (rolling + projection)

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SUMMARY

The equation for kinetic energy during the projection of a ball is given by E_k=(gmR^2)/4h, where g is the gravitational acceleration (9.81 m/s²), m is the mass of the ball, R is the radius, and h is the height of the ramp. This formula specifically accounts for the kinetic energy at the moment of projection, not at landing. To derive this equation, one must consider the moment of inertia of a solid sphere (I = 2/5mr²) and the total kinetic energy formula (K = 1/2mv² + 1/2Iw²). Additionally, the analysis requires understanding the time of flight in relation to gravitational acceleration and height.

PREREQUISITES
  • Understanding of gravitational acceleration (9.81 m/s²)
  • Familiarity with the moment of inertia of a solid sphere (I = 2/5mr²)
  • Knowledge of kinetic energy equations (K = 1/2mv² + 1/2Iw²)
  • Basic principles of projectile motion and energy conservation
NEXT STEPS
  • Research the derivation of the kinetic energy formula E_k=(gmR^2)/4h
  • Learn about the time of flight for a projectile in terms of gravitational acceleration and height
  • Study the relationship between radius, velocity, and time of flight for rolling objects
  • Explore the effects of rotational kinetic energy on total kinetic energy in rolling motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators seeking to clarify concepts related to kinetic energy and projectile motion.

foreverlostinclass
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Homework Statement
A ball is rolled down a ramp, then projected a distance R from the end of a curved ramp. The kinetic energy of the ball when it lands is given by the equation: E_k=(gmR^2)/4h, where g is the gravitational acceleration constant (9.81 m/s^2), m is the mass of the ball & h is the height from the ground to the bottom of the ramp.
Edit: Actually it's the kinetic energy when the ball is projected, not when it lands (sorry, misread the description).
Relevant Equations
moment of inertia of a solid sphere: I = 2/5mr^2
K = 1/2mv^2 + 1/2Iw^2
U = mgh
I'm not sure where the equation E_k=(gmR^2)/4h comes from & I also don't really know where to start either :(
 
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According to our rules, to receive help, you need to show some credible effort towards answering the question. How about telling us what you do know and how you would approach this problem?
Please read, understand and follow our homework guidelines, especially item 4, here
https://www.physicsforums.com/threads/homework-help-guidelines-for-students-and-helpers.686781/

Also, it would help if you posted the statement of the problem as was given to you. Note that you are saying that the kinetic energy of the ball is given at the moment of projection but it is not at all clear what you are asked to find.
 
foreverlostinclass said:
The kinetic energy of the ball when it lands is given by the equation: E_k=(gmR^2)/4h, where g is the gravitational acceleration constant (9.81 m/s^2), m is the mass of the ball & h is the height from the ground to the bottom of the ramp.
Edit: Actually it's the kinetic energy when the ball is projected, not when it lands (sorry, misread the description).
Relevant Equations: moment of inertia of a solid sphere: I = 2/5mr^2
K = 1/2mv^2 + 1/2Iw^2
U = mgh
It is still not quite true. That formula ignores the rotational KE.
To deduce it, you have to assume the bottom of the ramp is horizontal.
Find
  • how long it would take to land, in terms of g and h
  • the relationship between that time, R, and the velocity with which it leaves the ramp.
 

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