- #1

- 124

- 0

## Main Question or Discussion Point

Hi. I'm trying to derive a = (v^2)/r from the position of a particle moving in a circle. Since the equation for a particle moving in a circle is x(t) = r(

-Dan

**i**sin(wt) +**j**cos(wt)) where w is constant. I took two derivatives to find it's acceleration. I got a(t) = -rw^2(**i**cos(wt)+**j**sin(wt)). Now I'm stuck. How the heck and I getting rid of those trig functions? Thanks.-Dan