Deriving dA/dt = \omega x A: Proof for Constant Vector A and Vector \omega

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Homework Help Overview

The discussion revolves around proving the relationship dA/dt = ω x A, where A is a constant vector and ω is another vector representing angular velocity. Participants are exploring the implications of A being constant in the context of vector calculus and cross products.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand how to differentiate the expression involving a constant vector A and its relationship with the vector ω. There is a suggestion to consider the magnitude of A and its implications for the proof.

Discussion Status

The discussion is active, with participants offering hints and engaging in clarification. Some guidance has been provided regarding the differentiation of the magnitude of A, although there is still uncertainty expressed by one participant about its relevance.

Contextual Notes

There is a mention of the need to clarify whether A is constant in magnitude, which may influence the approach to the proof. Participants are navigating through the implications of this assumption.

nna
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I hope somebody can help me.. this is the problem i have to proof that if A is a constant vector then I can write its derivate as dA/dt = \omega x A.. where \omega is a vector, and the "x" is the cross product
 
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Welcome to PF!

Hi nna! Welcome to PF! :smile:

(have an omega: ω :wink:)
nna said:
I hope somebody can help me.. this is the problem i have to proof that if A is a constant vector then I can write its derivate as dA/dt = \omega x A.. where \omega is a vector, and the "x" is the cross product

(You mean "if A is constant in magnitude".)

Hint: if the magnitude is constant, then so is the magnitude squared, which is A.A. :wink:
 
Sorry :( but I don't understand how that helps...
 
Differentiate it …

what do you get? :smile:
 
ok ok thank you so much! it really helps... jaja it was very easy sorry
 

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