Deriving Magnetic Field from Helmholtz Coil Lab Data | Homework Question

  • Thread starter Thread starter 8008jsmith
  • Start date Start date
  • Tags Tags
    Coil Helmholtz
Click For Summary
SUMMARY

The discussion centers on deriving the magnetic field from data obtained in a Helmholtz coil experiment. The user is tasked with calculating the constant C using the slope of the graph (5.80) and the intercept (0.564) from their measurements. The relevant equation is (1/s²) = CBtot = C{Bh + 0.072Nμ0Ic/R}, where μ0 is 4π x 10⁻⁷ T m/A, N is 200 turns, and R is 0.105 m. The user seeks clarification on how to determine the moment of inertia (I) and the current (Ic) for accurate calculations.

PREREQUISITES
  • Understanding of Helmholtz coil principles and magnetic fields
  • Familiarity with the equation of motion for a bar magnet
  • Knowledge of moment of inertia and its calculation
  • Basic proficiency in graph interpretation and slope calculation
NEXT STEPS
  • Calculate the moment of inertia (I) for the bar magnet used in the experiment
  • Determine the current (Ic) based on the experimental setup and measurements
  • Explore the relationship between slope and magnetic field in Helmholtz coil experiments
  • Review the derivation of constants in magnetic field equations
USEFUL FOR

Students in physics courses, particularly those focusing on electromagnetism, lab instructors, and anyone conducting experiments with Helmholtz coils and magnetic fields.

8008jsmith
Messages
15
Reaction score
0

Homework Statement


I had a lab where we used Helmholtz coils to measure the period of a bar magnet (1/s2) vs output current. The graph of this is a straight line. Using the slope, I am supposed to be able to derive the C constant and then that divided by the intercept is supposed to yield the magnetic field.

Homework Equations


(1/s2) = CBtot= C{Bh + .072Nμ0Ic/R} = CBh + C (.072Nμ0/R) Ic

μ0 = 4π x 10-7 T m/A
N = 200 turns
R = 0.105 m
slope = 5.80
intercept = 0.564

C = m/4π2 I
I = moment of inertia

The Attempt at a Solution


[/B]
I've tried plugging the numbers into the equations to solve for C but I don't know what to use for Ic or I (Moment of inertia). I'm not even sure if this post makes all that much sense since all these variable are based on convention. Any help would be appreciated.
 
Physics news on Phys.org
It seems you have to calculate C from your graph's gradient, which will be equal to
8008jsmith said:
C (.072Nμ0/R)
according to you.
Then you use this value of C to get Bh from the y-intercept of the graph.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
5K
Replies
3
Views
3K
Replies
4
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
6
Views
5K
Replies
23
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 11 ·
Replies
11
Views
7K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 35 ·
2
Replies
35
Views
4K