Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Introductory Physics Homework Help
Deriving of the constants in Fourier Analysis
Reply to thread
Message
[QUOTE="Jufro, post: 4482094, member: 387451"] It is kinda simple, just like multiplying numbers, an odd times an even number results in an odd number. If you want a more rigorous definition then you can go back to the definition of odd and even. Assume g(x) is odd and f(x) is even. Then the product h(x)= f(x)*g(x). To check the parity of h(x) we find h(-x)= g(-x)*f(-x). Remembering what it means to be an odd or even function we get g(-x)*f(-x)= -g(x)*f(x)= -h(x). Leaving you with h(x)= -h(-x); otherwise known as an odd function. [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Introductory Physics Homework Help
Deriving of the constants in Fourier Analysis
Back
Top