Deriving some Laplace transforms

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Jamin2112
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Homework Statement



Find the Laplace transform of each of the following functions:

...

2. f(t)=eatcos(bt)

3. f(t)=tn, were n is a positive integer

Homework Equations



As you well know, taking the Laplace of f(t) means ∫f(t)e-stdt from 0 to ∞

The Attempt at a Solution



These problems are tripping me up, since integration by parts goes on forever.

∫eatcos(bt)e-stdt =
∫et(a-s)cos(bt)dt =

I suppose I should call et(a-s) "dv" (?)
----> v = t(a-s)/(a-s)
----> u = cos(bt)
----> du = -bsin(bt) dt

Still, I don't see where this gets me. Help, please!
 
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Do the integration by parts again, and then collect the integral you are interested in on one side.

This is like the following simpler integral:

[tex]\int e^x \sin x dx[/tex]
[tex]\int e^x \sin x dx = -e^x \cos x - \int -e^x \cos x dx[/tex] (one IBP)
[tex]\int e^x \sin x dx = -e^x \cos x + e^x \sin x - \int e^x \sin x dx[/tex] (second IBP)
[tex]2 \int e^x \sin x dx = e^x \sin x - e^x \cos x[/tex] (collect like terms)
etc...
 
hgfalling said:
Do the integration by parts again, and then collect the integral you are interested in on one side.

This is like the following simpler integral:

[tex]\int e^x \sin x dx[/tex]
[tex]\int e^x \sin x dx = -e^x \cos x - \int -e^x \cos x dx[/tex] (one IBP)
[tex]\int e^x \sin x dx = -e^x \cos x + e^x \sin x - \int e^x \sin x dx[/tex] (second IBP)
[tex]2 \int e^x \sin x dx = e^x \sin x - e^x \cos x[/tex] (collect like terms)
etc...

In the case of this particular problem, what integral am I interested in?
 
Well, you want

[tex]\int_{0}^{\infty} e^{t(a-s)} \cos (bt) dt[/tex]

which is related, but with, you know, constants and things.