Deriving the Formula for Sum of Cubes from Sum of Integers

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Homework Help Overview

The discussion revolves around deriving the formula for the sum of the first n cubes from the formula for the sum of the first n integers, specifically exploring the relationship that the sum of cubes is the square of the sum of integers.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants consider using the method of differences and telescoping series to derive the relationship. There is a focus on expanding expressions and summing both sides of an equation to relate the sums of different powers of integers.

Discussion Status

The discussion is active, with participants sharing different approaches and questioning how certain expansions and summations contribute to the derivation. There is no explicit consensus yet, but various lines of reasoning are being explored.

Contextual Notes

Participants are working under the constraints of deriving a formula without providing complete solutions, and there is an emphasis on understanding the relationships between the sums involved.

ehrenfest
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Homework Statement


Can someone help me derive the formula for the sum of the first n cubes from the formula for the sum of the first n integers that elucidates the reason why the former is the square of the latter?


Homework Equations





The Attempt at a Solution

 
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Well you could consider the sum from n=1 to N of (n+1)^4-n^4 and then expand using the method of differences
 
You mean use the fact that it telescopes?

Then you just get N^4-1? How does that help?
 
[tex](n+1)^4 - n^4 = 4n^3 + 6n^2 + 4n + 1[/tex] by the Binomial theorem.

Sum BOTH sides, and the LHS should get (N+1)^4 actually. Do you see how the RHS will be expressions in terms of the first N integers to the power of 3, 2, 1 and 0? You already know the cases for 0, 1 and 2, now you can work out 3.
 

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