Deriving the rms speed from the Maxwell speed distribution

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SUMMARY

The discussion focuses on deriving the root mean square (rms) speed from the Maxwell speed distribution, specifically solving the integral a∫₀^∞ v⁴e^(xv²) dv, where a and x are constants. The user initially struggled with u-substitution methods but ultimately resolved the problem by applying integration by parts multiple times. This approach effectively simplifies the integral, leading to the correct derivation of vrms.

PREREQUISITES
  • Understanding of Maxwell speed distribution
  • Familiarity with integration techniques, particularly integration by parts
  • Knowledge of definite and indefinite integrals
  • Basic grasp of exponential functions in calculus
NEXT STEPS
  • Study the properties of the Maxwell speed distribution in statistical mechanics
  • Learn advanced integration techniques, including integration by parts and u-substitution
  • Explore applications of rms speed in kinetic theory
  • Investigate the derivation of other statistical distributions in physics
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Students and professionals in physics, particularly those studying thermodynamics and statistical mechanics, as well as anyone interested in advanced calculus and integration techniques.

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Homework Statement



Find vrms from the Maxwell speed distribution.

Basically what I need to solve is the integral [itex]a\int_0^∞ \! v^4e^{xv^2} \, \mathrm{d}v[/itex]

Where ##a## and ##x## are constants.

Homework Equations



$$a\int_0^∞ \! v^4e^{xv^2} \, \mathrm{d}v $$

Where ##a## and ##x## are constants.

The Attempt at a Solution



I've tried u-substitution, subbing in u for ##v^2## and for ##v^{2.5}## but they end up not working.
 
Last edited:
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Nevermind, figured it out (integrate by parts a couple times).
 

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