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Deriving the surface area equation

  1. Feb 8, 2014 #1
    consider the following image

    4IrsvlR.png

    (the red is the surface area element and the green is the differential element that i'm integrating over)

    when we derived this in class, we treated the area formed by vectors a and b, as the area of a parallelogram. the thing is, a and b should be at right angles implying that rest of the angles should be right angles as well. if that's the case, then why can't i just treat the area formed from a and b, as a rectangle?

    well, that's what i attempted to try but failed. i get all the appropriate terms as they do in the surface area formula, except i get an extra term as shown in the link below, implying, perhaps.. that that extra term must go to zero. but i don't know why it should.

    if i'm incorrect in treating the shape formed from a and b as a rectangle, why is this incorrect?

    calculations:

    http://i.imgur.com/6MFO4xI.jpg
    (image was too large to put here)
     
  2. jcsd
  3. Feb 12, 2014 #2

    HallsofIvy

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    It's very difficult to read that- the colors do not show up on black very well! But to answer your question, the "a" and "b" on the surface are NOT vector IN the surface because it is not flat- they are tangent vectors to a curved surface and so do NOT form a rectangle in the surface. In order to calculate and area we have to project down to the xy- plane and the vectors are no longer necessarily perpendicular there.
     
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