- #1

chetzread

- 801

- 1

I found this on the Internet . The formula is

Surface Area = [tex] R^2 \displaystyle \int _0 ^ {2 \pi} \int _{0}^{\pi} \sin \theta d \theta d \phi [/tex]

I'm wondering why the limit of θ is from 0 to

Surface Area = [tex] R^2 \displaystyle \int _0 ^ {2 \pi} \int _{0}^{\pi} \sin \theta d \theta d \phi [/tex]

I'm wondering why the limit of θ is from 0 to

**π only ? why not from 0 to 2****π ? Because it's a perfect sphere...**