Deriving time peroid of a spring

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The discussion focuses on deriving the time period of a spring-mass system, expressed as T = 2π√(m/k). Key concepts include the force equation F = -kx, which indicates that the acceleration of the spring always moves towards the equilibrium point. The speed of the spring is highest at the equilibrium position, where displacement is zero. Additionally, the discussion touches on the mathematical representation of simple harmonic motion, showing that the functions x(t) = Acos(√(k/m)t) + Bsin(√(k/m)t) satisfy the motion equation. The period of these functions is also relevant to understanding the system's behavior.
thomas49th
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Hi all, I was wondering if we could go through how we get the time peroid for a spring with a mass m attached to it. The time period is:

T = 2pi sqrt(m/k)We know that F = -kx
We know the the the acceleration of a spring is always towards the equilibrium point
the speed can be measured negative and positive from the equilibrium point, as well as the displacement

The spring will be traveling fastest as it goes through the equilibrium point and it's displacement will be 0 at this point

Does that help towards the derivation?

Thanks
Tom
 
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F=ma

and the definition for simple harmonic motion will help
 
thomas49th said:
Hi all, I was wondering if we could go through how we get the time peroid for a spring with a mass m attached to it. The time period is:

T = 2pi sqrt(m/k)


We know that F = -kx
We know the the the acceleration of a spring is always towards the equilibrium point
the speed can be measured negative and positive from the equilibrium point, as well as the displacement

The spring will be traveling fastest as it goes through the equilibrium point and it's displacement will be 0 at this point

Does that help towards the derivation?

Thanks
Tom
F= ma= mx"= -kx.
Show that, for all numbers A and B,
x(t)= Acos(\sqrt{k/m}t)+ B sin(\sqrt{k/m}t)
satisfies that equation. What are the periods of those functions?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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