# Deriving Wien's Law from Planck's Formula

1. Apr 4, 2006

### Dorje

As a refresher exercise in modern physics, I want to derive Wien's displacement law:

$$\lambda_{max}T=2.898x10^{-3}mK$$

from Planck's formula:

$$R(\lambda)=(\frac{c}{4})(\frac{8\pi}{\lambda^4})(\frac{hc}{\lambda})(\frac{1}{\exp^(\frac{hc}{\lambda\kT})-1})$$

by differentiating R($$\lambda$$) and setting dR/d$$\lambda$$ = 0. I get to an expression like this:

$$\exp^(\frac{hc}{\lambda\kT})(hc - 5kT\lambda)+5kT\lambda=0$$

If it wasn't for the "5kT$$\lambda$$" term by itself on the left-hand side of the equation, the solution would simply be:

($$\lambda$$) (T) = hc / 5k

which is Wien's law. There must be something wrong though, or maybe there's a trick involved that I'm not seeing?

Thanks

2. Apr 5, 2006

### dextercioby

Yes, you're dealing with a typical transcendental equation, to which exact solutions cannot be found in most cases, this one included.

Daniel.

3. Dec 5, 2011

### peter2020210

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