MHB Deriving Y-Component of Uniform Electric Rod | E=-▽V

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The discussion focuses on deriving the y-component of the electric field from a uniform electric rod using the formula E = -▽V. The user calculated the derivative with respect to the vertical component "a" and arrived at the expression Κλl/(a sqrt(l^2+a^2)). Another participant confirmed the calculation but suggested that the constant appears unusual and provided an alternative expression for the y-component of the electric field: E_y = k_ell Q/(y sqrt(ell^2 + y^2)). The conversation emphasizes the importance of correctly applying mathematical principles in deriving electric field components.
Quintessential
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This is essentially the problem.

NDL0hSh.png


And this is what I did.

Realizing the following:

E = -▽V

I simply took the derivative in regards to the vertical component, in this case "a".

So:

-dV/da [the above formulae]

And I got the following:

Κλl/(a sqrt(l^2+a^2))

Does that seem about right?

**Sorry, I have no idea on how to operate the sexy mathjax characters.
 
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Quintessential said:
This is essentially the problem.

NDL0hSh.png


And this is what I did.

Realizing the following:

E = -▽V

I simply took the derivative in regards to the vertical component, in this case "a".

So:

-dV/da [the above formulae]

And I got the following:

Κλl/(a sqrt(l^2+a^2))

Does that seem about right?

**Sorry, I have no idea on how to operate the sexy mathjax characters.

Welcome to MHB, Quintessential! :)

Yep. That seems about right, although your constant looks a bit weird.

Anyway, since they are asking for the y component of the electric field at point P, I would write:

$$E_y = \frac{k_\ell Q}{y \sqrt{\ell^2 + y^2}}$$

(If you click Reply With Quote, you can see what the mathjax looks like. ;))
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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