Design a combination of Capacitors

Click For Summary
Both the user's and textbook approaches to designing capacitor combinations are valid, but the choice between them should consider the failure modes of the components. The discussion highlights that a series array of capacitors in parallel is less affected by an open failure, while a parallel array in series is less impacted by a closed failure. The prevalence of specific failure types, such as ceramic capacitors typically failing closed, can influence the preferred design. Additionally, cascading failures can lead to short circuits regardless of the initial configuration. Ultimately, the best approach depends on the specific application and failure considerations.
Shreya
Messages
187
Reaction score
64
Homework Statement
It is required to construct a 10mF capacitor which can be connected to a 200V Battery. Capacitors of Capacitance 10mF are available but they can withstand only 50V. Design a combination which can yield the desired result.
Relevant Equations
C=Q/V
My attempt was this:
IMG_20211016_153820.jpg

The textbook answer was:
Screenshot_20211016-153914_SelfStudys.png

Is my approach wrong?
 
Physics news on Phys.org
Shreya said:
Is my approach wrong?
Both approaches are valid.

If one wanted to choose between those two approaches (or other possible approaches), then it would be interesting to consider the effect of a failure (fail open or fail closed) of one of the components.
 
jbriggs444 said:
interesting to consider the effect of a failure (fail open or fail closed) of one of the components.
On failure of components, the textbook answer would be preferred,right?
 
Shreya said:
On failure of components, the textbook answer would be preferred,right?
Not necessarily. It depends on what failure type is most prevalent.

A series array of capacitors in parallel will not change its capacitance much if one element fails open.
A parallel array of capacitors in series will not change its capacitance much if one element fails closed.

But then one should also be concerned with the possibility of cascading failure. I do not build such things for a living, so I cannot offer an opinion on which approach is "best" in real life.

Edit: a quick trip to Google says that ceramic capacitors tend to fail closed (short circuit) on overload.

Cascading failure yields a short circuit either way.
 
Last edited:
Thread 'Chain falling out of a horizontal tube onto a table'
My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

Similar threads

Replies
2
Views
830
Replies
6
Views
322
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
317
Replies
20
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
4
Views
2K
  • · Replies 15 ·
Replies
15
Views
750
  • · Replies 14 ·
Replies
14
Views
1K