Designing priority encoder with 4-16 decoder and 8-1 MUX

In summary, the task is to design a 4 input priority encoder using a 4 to 16 decoder and a 8 to 1 multiplexer. The priority encoder works by giving priority to the highest input bit with a logical "1" and ignoring the rest of the lower priority bits. For the multiplexer design, 2 of them will be needed since only a 8 to 1 multiplexer can be used. The challenge is to relate the 2 outputs from the multiplexers into one. For the decoder design, there is confusion as to whether a priority encoder should be an encoder or a decoder. However, the end result will be a 2 bit output, which aligns with using two single bit output multip
  • #1
Kurokari
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0

Homework Statement


Design a 4 input priority encoder with a 4 to 16 decoder and a 8 to 1 multiplexer.

Homework Equations


Priority encoder is where when the highest priority bit is equal to a logical "1", then the rest of the lower priority input are ignored.

The Attempt at a Solution



For the MUX design, since we can only use a 8 to 1 MUX, means we'll have to use at least 2 of them. But I'm not very sure on how to relate the 2 outputs into one.

For the decoder design, I'm just confused. Shouldn't a priority encoder be a encoder, while a decoder is used to decode input? Is it possible that the question I have meant something else but a decoder?
 
  • #3
The end result will be a 2 bit output, yes? That fits with needing two single bit output multiexers.
Each multiplexer would need (in principle) 11 inputs, no?
As for encoder versus decoder, the distinction is a bit artificial. I guess that decoders typically arrange that no two different inputs vectors produce the same output, whereas encoders typically cannot do that.
 

FAQ: Designing priority encoder with 4-16 decoder and 8-1 MUX

1. How do you design a priority encoder with a 4-16 decoder and an 8-1 MUX?

To design a priority encoder with a 4-16 decoder and an 8-1 MUX, you will need to first determine the number of input lines and output lines required for the encoder. Then, you will need to use a truth table and Karnaugh maps to simplify the logic and create the necessary circuits for the encoder. Finally, you will need to connect the encoder output to the input of the 4-16 decoder and the output of the decoder to the input of the 8-1 MUX.

2. What is the purpose of a priority encoder in digital circuits?

A priority encoder is used to prioritize multiple input signals and convert them into a binary output code. This is useful in situations where certain inputs need to take precedence over others, such as in a control system or in data transmission. It helps reduce the complexity of the circuit and ensures that important signals are not lost or ignored.

3. How does a 4-16 decoder work?

A 4-16 decoder is a combinational circuit that takes a 4-bit input and produces a 16-bit output, with only one output line being active at a time. The active output line corresponds to the binary value of the input. For example, if the input is 0101, the fifth output line will be active (since it represents the binary value 0101). All other output lines will be inactive.

4. What is the function of an 8-1 MUX?

An 8-1 MUX (multiplexer) is a digital circuit that selects one of eight input signals and passes it onto a single output line. The selection of the input signal is controlled by a set of select lines. This is useful for routing data or control signals to different destinations based on the value of the select lines.

5. Can a priority encoder with a 4-16 decoder and an 8-1 MUX be cascaded to handle more inputs?

Yes, a priority encoder with a 4-16 decoder and an 8-1 MUX can be cascaded to handle more inputs. By connecting the output of one encoder to the input of another, you can expand the number of inputs that can be prioritized. However, it is important to carefully design the cascaded circuit to avoid any glitches or delays in the output.

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