Determinant of 4x4 Matrix with Given Value and Variable Columns

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SUMMARY

The determinant of the modified 4x4 matrix A, where the second column is transformed to 9v2 + 5v3 and the third column to 5v2 + 8v3, is calculated based on the original determinant detA = -2. The determinant remains unchanged when adding columns, but multiplying a column by a scalar affects the determinant proportionally. The final determinant is determined to be -18, as it is the product of the scalar multiplication of the second column (9) and the original determinant (-2).

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Homework Statement


If a 4x4 matrix A with rows v1, v2, v3 and v4 has determinant detA =-2

then

then det (v1, 9v2+5v3, 5v2+8v3, v4) =___?


Homework Equations





The Attempt at a Solution



Ok, so I think it should be -18 (since 9 x -2). I mean the determinant should not change when adding columns to each other, however multiplying should have an effect, but I am not quite sure what happened to the v3, like do I multiply the determinant by 8, or 5, or none?
 
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I'll give you a sample, det(v1,9*v2+5*v3,v3,v4)=
det(v1,9*v2,v3,v4)+det(v1,5*v3,v2,v5)=
9*det(v1,v2,v3,v4)+5*det(v1,v3,v3,v4). What's that? Now what happens if you put the linear combination in for v3 as well?
 

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