Determinant of a Finite Field 2x2 Matrix

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SUMMARY

The determinant of the 2x2 matrix |1 1| |2 1| in the finite field Z3 is calculated as follows: (1 x 1) - (1 x 2) = 1 - 2 = -1. However, in Z3, -1 is equivalent to 2, as both numbers differ by a multiple of 3. Thus, the final determinant is 2. This illustrates the concept of equivalence in modular arithmetic, specifically in Z3.

PREREQUISITES
  • Understanding of finite fields, specifically Z3.
  • Knowledge of matrix determinants and their calculations.
  • Familiarity with modular arithmetic and remainders.
  • Basic algebraic manipulation skills.
NEXT STEPS
  • Study the properties of finite fields, focusing on Zp for prime p.
  • Learn more about matrix operations in modular arithmetic.
  • Explore the concept of equivalence classes in modular systems.
  • Investigate applications of determinants in linear algebra over finite fields.
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Students studying linear algebra, mathematicians interested in modular arithmetic, and educators teaching finite fields and determinants.

rehcarlos
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Homework Statement



Find the determinant of:
|1 1|
|2 1|

The field is Z3.

Homework Equations



The field is Z3, that is, to multiply two numbers, you first multiply then take the remainder of the division by 3.

The Attempt at a Solution


I tried:
( 1 x 1 ) - ( 1 x 2 )
1 x 1 will be: 1x1 = 1 => then get the remainder of the division by 3 that is 1
1 x 2 will be: 1 x 2 = 2 => then get the remainder of the division by 3 that is 2

So, the determinant would be 1 - 2 = -1 => then get the remainder of the division by 3 that is -1

But the answer is 2
 
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rehcarlos said:

Homework Statement



Find the determinant of:
|1 1|
|2 1|

The field is Z3.

Homework Equations



The field is Z3, that is, to multiply two numbers, you first multiply then take the remainder of the division by 3.

The Attempt at a Solution


I tried:
( 1 x 1 ) - ( 1 x 2 )
1 x 1 will be: 1x1 = 1 => then get the remainder of the division by 3 that is 1
1 x 2 will be: 1 x 2 = 2 => then get the remainder of the division by 3 that is 2

So, the determinant would be 1 - 2 = -1 => then get the remainder of the division by 3 that is -1

But the answer is 2

In Z3, -1=2. Any two numbers that differ by a multiple of 3 have the same remainder when divided by 3.
 
I know it may be simple, but I'm still confuse,

-1 divided by 3 has a remainder of -1
2 divided by 3 has a remainder of 2

So I don't get how they have the same remainder
 
rehcarlos said:
I know it may be simple, but I'm still confuse,

-1 divided by 3 has a remainder of -1
2 divided by 3 has a remainder of 2

So I don't get how they have the same remainder

To say Z3 is about 'remainders' isn't quite accurate. Two number are equal in Z3 if they differ by a multiple of 3. That's the sense in which they have the same remainder. 2-(-1)=3*1.
 
Ok then,

Thanks!
 

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