Determine acceleration when lifting a bucket.

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Homework Help Overview

The problem involves determining the acceleration of a bucket being lifted out of a well using a rope and pulleys. The mass of the bucket and water is denoted as m, and the force applied by a person pulling the rope is F. The discussion centers around the forces acting on the bucket, including gravitational force and the applied force.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the forces acting on the bucket, specifically the upward force of 3F and the downward gravitational force mg. There is an exploration of how these forces relate to the acceleration of the bucket.

Discussion Status

Participants are actively engaging with the problem, questioning assumptions about the forces involved and clarifying the application of Newton's Second Law. Some have provided insights into the net force acting on the bucket, while others are still grappling with the implications of these forces on acceleration.

Contextual Notes

There is an emphasis on neglecting the mass of the ropes and pulleys, as well as frictional forces, which may affect the interpretation of the forces involved. Participants are also reflecting on their understanding of the problem and expressing uncertainty about their reasoning.

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Homework Statement


A bucket of water is raised up out of
a well with a device of the rope, and
pulleys as shown in figure. The bucket is hanging from the
the lower hook and the upper hook is
attached to a fixed cross bar of the well. If
the mass of the bucket and the water together
is m, and the man pulls the rope with
a force F, how large is the span's acceleration
up? The mass of ropes and pulleys
can be neglected, as well as frictional forces.

http://bayimg.com/daOdPAAde

Answer: (3F/m)-g

Homework Equations



F=mg and maybe F=ma

The Attempt at a Solution



Due to gravity there is a force downward. Since the mass of the bucket and the water together is m, the downward force is mg. From figure I see that the device is constructed so that the cable runs three times between the bucket and the hook before I pull it. Therefore the force required for the bucket to move upwards is F=mg/3≥.

From here I am stuck. I know that F=ma and therefore a=F/m. However, if I insert F=mg/3 and m=mg, I get the wrong answer.
 
Last edited by a moderator:
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You are forgetting about the weight. Acceleration is determined by the net force in F=ma.
 
LawrenceC said:
You are forgetting about the weight. Acceleration is determined by the net force in F=ma.

The weight as in F=mg. Please explain, I can´t really see what I am doing wrong.
 
The force up is 3F. What is the force down? You are considering it as if the bucket full of water were sitting on a frictionless horizontal surface and you are pulling it horizontally.
 
Last edited:
LawrenceC said:
The force up is 3F. What is the force down? You are considering it as if the bucket full of water were sitting on a frictionless horizontal surface and you are pulling it horizontally.

I understand that the force upwards is 3F. And the force down is F=mg, caused by gravity. Is that right? How is now acceleration related. Well, F=ma, so 3F=3ma. From "you are forgetting about the weight", I understand it as 3ma-mg. So far so right? Sorry about my incompetence of the subject.
 
The force up is 3F. The force down is mg. The net force is 3F-mg. The net force is what Newton's Second Law equates to the product of mass and acceleration. The mass is m not 3m.
 
LawrenceC said:
The force up is 3F. The force down is mg. The net force is 3F-mg. The net force is what Newton's Second Law equates to the product of mass and acceleration. The mass is m not 3m.

Thank you LawrenceC. It makes sense now.
 

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