Determine currents Ia, Ib and Ic

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    Currents Ib Ic
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Discussion Overview

The discussion revolves around determining the currents Ia, Ib, and Ic in a complex electrical network using various methods such as superposition, mesh analysis, and nodal analysis. Participants share their calculations, approaches, and challenges encountered while solving the problem.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents a calculation for the total resistance using complex impedances and applies Ohm's Law to find currents.
  • Another suggests using mesh equations instead of superposition, claiming it could simplify the process.
  • Several participants express frustration with their calculations yielding inconsistent results.
  • Mesh equations are proposed, with some participants attempting to derive expressions for Ia and Ib.
  • One participant suggests solving symbolically before substituting complex values to avoid errors in calculations.
  • Another proposes a nodal analysis approach, providing a node equation and expressing currents in terms of node potentials.
  • Discussions include corrections to algebraic manipulations and the importance of careful calculations in complex arithmetic.
  • Participants share numerical values for Vx, Ia, and Ib, with some expressing uncertainty about the accuracy of their results.
  • One participant mentions the potential benefits of using software or calculators for complex arithmetic to reduce errors.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best method to solve the problem, with multiple approaches being discussed and varying degrees of success reported in calculations. Some express confidence in their results, while others remain uncertain and seek validation.

Contextual Notes

Participants highlight the complexity of calculations involving complex numbers and the potential for errors in manual computations. There are unresolved steps in the calculations, and assumptions about the accuracy of derived expressions are not fully verified.

Who May Find This Useful

Students and practitioners in electrical engineering or physics who are dealing with circuit analysis, particularly those working with complex impedances and seeking different methods for solving circuit problems.

  • #61
I did and it works.
The answer is :

Ib= 0.057- 0.0356j
 
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  • #62
agata78 said:
I did and it works.
The answer is :

Ib= 0.057- 0.0356j

Okay! :smile:

So you'll have to analyze the logic of whatever method you used before in order to spot where the sign got lost.
 
  • #63
Thank you! Two more to go!
 

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