Determine how many licence plates would cost $100

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The discussion centers on calculating the number of vehicle license plates that would cost exactly $100, given a specific cost structure for letters and digits. Each license plate consists of three letters followed by three digits, with letters costing $1 to $26 based on their position in the alphabet and digits costing $n for n>0 and $10 for 0. The solution reveals that there are 1287 unique license plates that can be produced for this cost, derived through combinatorial mathematics involving indistinguishable balls and distinguishable cells.

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In a certain state of a certain country, each vehicle license plates have exactly three letters followed by three digits. We are told that to produce such a license plate, it costs $n for each digit n>0 and $10 for each digit 0. For letters the cost is proportional to the position of the letter in the alphabet, namely \$1 for A, \$2for B, so on and so forth, upto $26 for Z.

Now, how to determine how many license plates would cost $100?

Answer:- I don't understand how to answer this question. I think linear programming will help here.
 
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This question seems to be difficult and maybe linear programming can help here.
 
Dhamnekar Winod said:
In a certain state of a certain country, each vehicle license plates have exactly three letters followed by three digits. We are told that to produce such a license plate, it costs $n for each digit n>0 and $10 for each digit 0. For letters the cost is proportional to the position of the letter in the alphabet, namely \$1 for A, \$2for B, so on and so forth, upto $26 for Z.

Now, how to determine how many license plates would cost $100?

Answer:- I don't understand how to answer this question. I think linear programming will help here.
Hello,
After working on finding out the answer to this question, eventually i suceeded. The answer to this question is 1287 license plates would cost \$100.

Justification to the answer:-

The maximum possible cost is \$108 of the license plate having ZZZ 000. Finding the number of license plates having the cost of \$100 is equivalent to finding how many ways 8 indistinguishable balls can be put into 6 distinguishable cells. So $\binom{n+r-1=13}{r=8}=1287 $ license plates.
 

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