MHB Determine how many licence plates would cost $100

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Each vehicle license plate consists of three letters followed by three digits, with costs varying based on the letters' positions in the alphabet and the digits used. The cost for digits is $n for n>0 and $10 for 0, while letters cost $1 to $26 based on their alphabetical order. The maximum cost for a license plate is $108, represented by "ZZZ 000." To find how many license plates total $100, the problem translates to distributing 8 indistinguishable items into 6 distinguishable categories, resulting in 1287 possible combinations. Thus, 1287 license plates can be produced for $100.
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In a certain state of a certain country, each vehicle license plates have exactly three letters followed by three digits. We are told that to produce such a license plate, it costs $n for each digit n>0 and $10 for each digit 0. For letters the cost is proportional to the position of the letter in the alphabet, namely \$1 for A, \$2for B, so on and so forth, upto $26 for Z.

Now, how to determine how many license plates would cost $100?

Answer:- I don't understand how to answer this question. I think linear programming will help here.
 
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This question seems to be difficult and maybe linear programming can help here.
 
Dhamnekar Winod said:
In a certain state of a certain country, each vehicle license plates have exactly three letters followed by three digits. We are told that to produce such a license plate, it costs $n for each digit n>0 and $10 for each digit 0. For letters the cost is proportional to the position of the letter in the alphabet, namely \$1 for A, \$2for B, so on and so forth, upto $26 for Z.

Now, how to determine how many license plates would cost $100?

Answer:- I don't understand how to answer this question. I think linear programming will help here.
Hello,
After working on finding out the answer to this question, eventually i suceeded. The answer to this question is 1287 license plates would cost \$100.

Justification to the answer:-

The maximum possible cost is \$108 of the license plate having ZZZ 000. Finding the number of license plates having the cost of \$100 is equivalent to finding how many ways 8 indistinguishable balls can be put into 6 distinguishable cells. So $\binom{n+r-1=13}{r=8}=1287 $ license plates.
 
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