Determine how much of the sky can be imaged in a single night

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SUMMARY

To determine how much of the sky can be imaged in a single night, one must calculate the total number of exposures possible within the 12-hour timeframe, given the telescope's field of view and readout time. The visible celestial sphere is 26360.64 square degrees, and the telescope's field of view is 2100 x 1700 arc seconds. With a readout time of 5 seconds per exposure, the total number of exposures can be calculated, allowing for the determination of the total area imaged over the specified duration.

PREREQUISITES
  • Understanding of celestial sphere measurements
  • Familiarity with telescope specifications and field of view calculations
  • Knowledge of time management in astrophotography
  • Basic arithmetic for area calculations
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  • Calculate the total number of exposures possible in 12 hours with a 5-second readout time
  • Research the conversion of arc seconds to square degrees for field of view
  • Explore astrophotography techniques for maximizing imaging efficiency
  • Learn about celestial navigation to optimize telescope positioning
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Astronomy students, astrophotographers, and amateur astronomers looking to optimize their imaging sessions with telescopes.

willmc
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Hello,
I am doing an assignment, and am required to work out how much of the sky can be imaged in a single night by a telescope.

If the amount of celestial sphere that is visible for this particular site is 26360.64 degree squared for the 12 hours.

The field of view of the telescope is 2100 x 1700 arc seconds, with a read out time of 5 seconds per exposure.

How would i figure out how much sky can be imaged over 12 hours?

I really need help.. this is due tonight :/
Regards
William
 
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