Determine if subset is subspace of R3. Need Help.

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The subset defined by {[x,y,z] | x,y,z in R, z = 3x+2} is not a subspace of R3 because it does not contain the zero vector (0, 0, 0), which does not satisfy the equation. To verify if a subset is a subspace, one must check closure under addition and scalar multiplication specifically for elements within the set, not arbitrary vectors from R3. The addition method requires demonstrating that the sum of any two elements from the set remains in the set, and similarly for scalar multiplication. Understanding the distinction between elements in the defined set and general vectors in R3 is crucial for this determination. Thus, the subset fails to meet the criteria for being a subspace of R3.
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1. {[x,y,z] | x,y,z in R, z = 3x+2}.
How do I determine if this subset is a subspace of R3? Am I wrong when I say this set contains the zero vector? If this is the case, then I have to use the addition and multiplication closure methods, right?

Thanks
 
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digitol87 said:
{[x,y,z] | x,y,z in R, z = 3x+2}.
How do I determine if this subset is a subspace of R3? Am I wrong when I say this set contains the zero vector?
Yes, wrong. (0, 0, 0) does not satisfy z = 3x + 2.
digitol87 said:
If this is the case, then I have to use the addition and multiplication closure methods, right?

Thanks
 
Mark44 said:
Yes, wrong. (0, 0, 0) does not satisfy z = 3x + 2.

OK, That's a good first step. I'm still a little confused as to how to apply the addition method.
can I add [x,y,z] + [a,b,c] then get [x+a, y+b, z+c] ? Then what?

Thanks.
 
No, you have to take two elements in the set, and show that their sum is in the set. You can't take any old arbitrary vector in R3. Also, it must be true that if v is an element in the set, then kv is also in the set.

What must be true for any element in your set? I.e., how do you distinguish between vectors in your set and plain old vectors in R3?
 
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