- #1

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## Homework Statement

Determine the inductance of a solenoid with 650 turns in a length of 21 cm. The circular cross section of the solenoid has a radius of 4.2 cm.

## Homework Equations

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- Thread starter matt72lsu
- Start date

- #1

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Determine the inductance of a solenoid with 650 turns in a length of 21 cm. The circular cross section of the solenoid has a radius of 4.2 cm.

???

- #2

rl.bhat

Homework Helper

- 4,433

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L = μo*N^2*A/l.

where N is number of turns,

A area of cross section of the coil and

l is the length of the coil.

- #3

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Ok so I did L = (1.26e-6)(650)^2(.00882) / .21 = 2.24e-2 H = 22.4mH. I got it wrong however. Where did I go wrong?

- #4

rl.bhat

Homework Helper

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Check the area of the coil.

- #5

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would area = .01764? (radius^2 (in meters) * .21)

- #6

rl.bhat

Homework Helper

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Area of cross section of the coil iswould area = .01764? (radius^2 (in meters) * .21)

- #7

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ok i'm an idiot. i got it wrong again. this was my equation: L = (1.26e-6)(650)^2(1.1466)/.21. i multiplied that answer by 1000 to get mH

- #8

rl.bhat

Homework Helper

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How did you get this?

Area = π*(4.2*10^-2)^2 m^2 = 55.42*10^-4 m^2

- #9

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ok i got it! i used n = 650 (is that not what n is?). Anyways... thanks for all your help (and patience). I really appreciate it!

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