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Determine inductance of a solenoid

  • Thread starter matt72lsu
  • Start date
  • #1
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Homework Statement


Determine the inductance of a solenoid with 650 turns in a length of 21 cm. The circular cross section of the solenoid has a radius of 4.2 cm.


Homework Equations



???

The Attempt at a Solution

I've looked all over my textbook and cant come up with a possible equation(s). Help!!!
 

Answers and Replies

  • #2
rl.bhat
Homework Helper
4,433
5


L = μo*N^2*A/l.
where N is number of turns,
A area of cross section of the coil and
l is the length of the coil.
 
  • #3
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Ok so I did L = (1.26e-6)(650)^2(.00882) / .21 = 2.24e-2 H = 22.4mH. I got it wrong however. Where did I go wrong?
 
  • #4
rl.bhat
Homework Helper
4,433
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Check the area of the coil.
 
  • #5
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would area = .01764? (radius^2 (in meters) * .21)
 
  • #6
rl.bhat
Homework Helper
4,433
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would area = .01764? (radius^2 (in meters) * .21)
Area of cross section of the coil is π*r^2.
 
  • #7
94
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ok i'm an idiot. i got it wrong again. this was my equation: L = (1.26e-6)(650)^2(1.1466)/.21. i multiplied that answer by 1000 to get mH
 
  • #8
rl.bhat
Homework Helper
4,433
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(1.1466)/
How did you get this?
Area = π*(4.2*10^-2)^2 m^2 = 55.42*10^-4 m^2
 
  • #9
94
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ok i got it! i used n = 650 (is that not what n is?). Anyways... thanks for all your help (and patience). I really appreciate it!
 

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