- #1

stevencarlover

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## Homework Statement

A long straight solenoid of cross-sectional area 400 cm^2 is wound with 10 turns of wire per centimeter, and the winding carry a current in the direction shown (downward). A small ring of radius 5.00 cm and resistance 0.300 ohms is placed at the center of the solenoid. If the current in the solenoid increases from 20.0 Amps to 60.0 Amps in 2.50 seconds, find the direction and magnitude of the current induced in the ring during this period.

## Homework Equations

M = (Mu0)(A)(N1)(N2)/L

emf = M(di/dt)

emf = I *R

## The Attempt at a Solution

Since the question does not give values for N1, N2, and L I do not know how to find the mutual inductance and thus the induced current in the ring.