Determine limiting behavior as t goes to infinity(Differential Equation)

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SUMMARY

The discussion focuses on determining the limiting behavior of solutions to the differential equation \(\frac{dy}{dt}=4-y^2\) as \(t\) approaches infinity for all initial values \(y_0 = y(0)\). The constant solutions identified are -2 and 2, with the solution at 2 being stable. It is concluded that while the stable solution at 2 attracts nearby initial values, solutions starting far from this point may diverge to infinity instead of converging to the stable solution.

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Homework Statement


Determine the limiting behavior of solutions as t \rightarrow \infty, for all possible values y_0 = y(0)


Homework Equations



\frac{dy}{dt}=4-y^2


The Attempt at a Solution



I've obtained the constant solutions, they are -2 and 2. I sketched dy/dt to determine the monotonicity, and found that the constant solution 2 is stable. My question is whether this stable solution is what determines the behavior as t goes to infinity.

I just started taking differential equations and I'm trying to get used to the language and the nature of the questions. Since 2 is a stable solution, that should mean that all initial values of y should go to 2 as time passes correct?
 
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No. A solution doesn't have to approach the stable solution unless it starts out near the stable solution. Otherwise, it might just go to infinity.
 
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