I don't think you can get the horizontal components from t1 or t2 using just the horizontal force required. you can form a triangle with the vectors t1, t2 and the required force, and you know all angles and one side of this triangle, so you can compute the other two sides.
What I would do however is just solve the two equations that you get if you use the fact that both the total horizontal and vertical force must be 0.
for horizontal you get -t1*sin(30) + t2*cos(30) - 80cos(45) = 0
for vertical you get ....
you can get the first equation in the form t1 = (expression with only t2)
and substitute that in the second.