Determine the acceleration after 6 seconds.
s(t) = sqrt12t - 8 where s is in metres and t is in seconds.
The Attempt at a Solution
this is where i don't understand...they got a positive value for 36 in the book and i got a negative value...here is my work below that got me to a negative value...what did i do wrong?
a=v'(t)=0*sqrt12t-8 - 6/sqrt12t-8*6/(sqrt12t-8)^2
= - 36/sqrt12t-8/(sqrt12t-8)^2
= - 36/(12t-8)^3